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守方lv0兵種能力分析

本主题由 猪的首领 于 2008-8-3 01:16 移动

守方lv0兵種能力分析

注意:
3 C+ Z: b7 N  `* E5 E2 h$ G1.此表為算至小數點下三位四捨五入的結果,會跟實際值有所出入$ r: X6 R( z/ E5 {7 ?6 G
2.此表為防守方之數值,故維持費不增加
7 F3 W0 ]/ Z" n! M7 N3.此表為防守方之數值,故無強擊效果發動
9 a( g& t- [; W# l4.此表皆無兵工廠能力加成% F# {8 [7 z+ u  A2 f' o4 K
5.此表不考慮減免維持費之科技( u7 p' [+ o+ G) d" }
& n- k2 |4 N! p0 q
符號說明: A=攻擊力 D=防禦力 x=無限大8 @- x6 H0 {* q2 t
P=訓練人口 W=木材7 L; U. @' K' ]5 e/ G) s
S=硫磺(潛水艇的S=水晶)
1 T. ^0 t. D$ U0 [+ j# QG=維持費 RANK=排名1 a) p0 g  U. ?; ^
A/P=每單位訓練人口所產的攻擊力; ~/ Y: n% h; a  a  z. [5 S
剩下以此類推8 e% I0 P) v, t/ p
陸軍
" r0 W8 S  z' E1 G  P# e0 a! s& m__________A/P_____RANK__A/W___RANK__A/S____RANK__A/G____RANK! Y: P$ p/ E  \% ^6 b& i
投石兵_____7.000__07____0.175__05____x______01____0.875__080 E5 X/ J8 T, m" ~
劍士_______9.000__05____0.383__01____1.125__02____1.125__047 V- j! X  ?& }" O3 U* j% ~( P
方陣兵_____6.000__08____0.231__03____0.375__05____1.000__06
2 W" b4 x# o- w6 w+ U. t衝撞車_____1.750__11____0.071__10____0.109__10____0.269__11) t9 K3 z0 s9 u# c0 W
弓箭手____10.000__04____0.233__02____0.465__04____1.250__03# I* X) f! `7 Z$ V( ^; S
投石車_____3.600__10____0.105__06____0.155__08____0.500__097 [) F8 G6 a; {
火槍兵____11.429__03____0.225__04____0.519__03____1.379__02% M* ^3 l9 y# s5 r0 U* f
迫擊炮_____5.333__09____0.048__11____0.068__11____0.500__099 y7 L8 U$ r0 Q9 H; i  ~' v
蒸氣巨人__16.667__01____0.087__09____0.140__09____1.471__01
( E3 M( I( B: w/ d$ {旋翼機____14.000__02____0.090__07____0.167__07____1.155__05
2 ^3 H& n& X$ m$ D4 ^8 H9 \轟炸氣球___8.333__06____0.088__08____0.228__06____0.877__07
# |) J3 z+ @' v* J, y7 w" \
9 Q  n% }2 d  Q7 Q+ K; p+ O+ h! r__________D/P____RANK__D/W____RANK__D/S____RANK__D/G____RANK: j9 R, E. H( }' v& H; ]
投石兵_____6.000__08____0.150__06____x______01____0.750__07
- R) `3 X! X7 Z* c劍士_______7.000__06____0.298__02____0.875__02____0.875__06
5 j" p( Y6 j9 }- K# F, W' k方陣兵____13.000__03____0.500__01____0.813__03____2.167__02* }5 {% |" ^* E# ]* p, v. v7 m
衝撞車_____2.250__11____0.091__07____0.141__09____0.346__11& w, K  T- `7 S# _: \; }/ G8 f
弓箭手____10.000__04____0.233__03____0.465__04____1.250__03. p2 G2 c# X" J$ U" G' K
投石車_____2.800__10____0.082__09____0.121__10____0.389__10
; Q/ n& z% s+ f$ \7 _7 a3 I+ ^  S火槍兵_____9.143__05____0.180__04____0.416__05____1.103__05- c0 _# s: H* P( z
迫擊炮_____5.333__09____0.048__11____0.068__11____0.500__09* Q/ }. r* h& P: U2 q
蒸氣巨人__30.333__01____0.158__05____0.255__06____2.676__01) J+ P. J1 L, j3 r4 M
旋翼機____14.000__02____0.090__08____0.167__08____1.155__04$ i. i$ [; u4 d+ A/ G  U* E; L
轟炸氣球___6.875__07____0.073__10____0.188__07____0.724__08
& \0 `# v) D$ o# u3 D- V  G5 {( ]) R: ?/ [2 H  k  `) v
海軍
# F9 z2 R5 L% L# }* k# r__________A/P____RANK__A/W____RANK__A/S____RANK__A/G____RANK" Y- {8 u9 k  k6 U# X: ?
衝撞船_____2.667__07____0.286__04____0.762__02____0.800__073 O; P* q, \+ s
強弩船_____4.000__06____0.278__05____0.690__04____0.833__069 [9 _! R2 W" t' \
噴火船_____8.000__02____0.381__01____0.519__06____0.889__03
" c# T: k: [& L" ?& P投石船_____6.000__05____0.347__03____0.789__01____1.053__02
' d' ~; o) _5 l$ t0 \, o迫擊炮船___7.273__03____0.351__02____0.567__06____1.231__01
( {& g5 z/ {/ ~( y4 J, m* B明輪衝撞船_8.333__01____0.195__06____0.599__05____0.877__04
5 e/ F' b: I0 V; P% S2 ]4 T& Q. i2 A; f+ M淺水挺_____6.875__04____0.223__07____0.291__07____0.873__058 h1 c2 \7 l" `5 ?  k8 c

# O+ Y7 D2 i, q7 [* S2 G: D__________D/P____RANK__D/W____RANK__D/S____RANK__D/G____RANK, @/ j! k% ?( o' B% a7 R
衝撞船_____2.667__07____0.286__06____0.762__03____0.800__06' G& G7 _  l/ \! M  z
強弩船_____7.280__04____0.506__01____1.255__01____1.517__02! v( e9 \6 x( h7 u" e) ?. M
噴火船_____8.000__02____0.381__03____0.519__07____0.889__05, q9 h* P0 o/ m0 a9 D
投石船_____6.000__06____0.347__05____0.789__02____1.053__041 D$ Q* S* o4 U. @: h$ M3 D8 U
迫擊炮船___7.273__05____0.351__04____0.567__04____1.231__03& V0 U) @: v1 p7 p
明輪衝撞船_7.500__03____0.175__07____0.539__05____0.539__07* w. R2 X* ?8 l9 m# ^) u* O2 a& R& d8 a
潛水艇____12.594__01____0.409__02____0.533__06____1.599__01" ^/ g1 s! u! K9 B7 |& p5 _$ i2 o

/ s% Z$ i( {# _分析:
2 d6 {5 D* A5 v9 ^0 e1 @9 D1 d根據其數值可知, f2 {, C% h6 v
陸軍:
( z5 J  Z" d9 B# r7 X0 B3 T防守方缺人口時生產蒸氣巨人(A/P、D/P均為最高)為佳
- l+ o& k( A8 k5 ?) N防守方缺木材時生產劍士(A/W為最高)及方陣兵(D/W最高)為佳
4 H! |, ?) f2 R8 U防守方缺硫磺時生產投石兵(A/S、D/S均為最高)為佳/ a. K% ^* a, s
防守方缺錢時生產蒸氣巨人(A/G、D/G均為最高)
# ^7 F: g3 K# t( Y0 U
3 }& d& l/ Y  \8 _海軍:  `8 |- Z4 \0 R& L8 A
防守方缺人口時生產明輪衝撞船(A/P為最高)及潛水艇(D/P為最高)為佳6 D% c* Q3 v2 G
防守方缺木材時生產噴火船(A/W為最高)及強弩船(D/W為最高)為佳
: X2 S4 ]( b' F" n防守方缺硫磺時生產投石船(A/S為最高)及強弩船(D/S為最高)為佳
+ v/ D8 {$ a& o' N防守方缺錢時生產迫擊炮船(A/G為最高)及潛水艇(D/G為最高)為佳- @$ V+ d7 `6 v5 Y

" E1 r$ p0 M; ~1 ]  V本人的建議不考量速度! L* r9 [% ]# B1 E4 I
小弟我的編軍建議是考量攻擊力最高+防禦力最高的混編以增加打擊敵人的能力+ m; y7 X- [/ S1 Y0 E- ^+ X
個人認為看A/G、D/G去考量就可以了; f& E1 O& |$ Z5 k" D" e

6 d; |5 K" {3 _9 Y5 C1 J4 S: I综合分析顯示
" T9 s# |8 ~7 Z  Z防守方最優秀的陸軍攻擊兵:火槍兵; `0 U- l/ G: ^: T- X9 k0 P
防守方最優秀的陸軍防禦兵:方陣兵
! ?* J" U0 w: K8 a1 h防守方最優秀的海軍攻擊兵:投石船; \- Y2 `" b$ v, P! Z' e
防守方最優秀的海軍防禦兵:強弩船
7 i0 t) K" I- X  c- }5 E7 [+ f& j: Z
- ~  M* i/ l) P6 R; D
附註:因為醫生和廚師數值都小的可憐,沒有比較價值,所以沒有分析這兩種兵
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